Thread: help with cin.get() program trying to use cin.get instead of getch()

Hi ! everyone I was trying to use cin.get() like we used to use getch() .
By which I mean using getch()/cin.get() to pause screen till a character is entered.

Here is the code

Code:

#include<iostream>

using namespace std;

int main()
{
     
    cout<<"hi";
   
    cin.get();
}

but when I tried it with this code it failed in first try

Code:

#include<iostream>

using namespace std;

int main()
{
    char a;
    int i;
    
    cout<<"hi";
    
    a=i=cin.get();
    
    cout<<a<<endl<<i;

    
    cin.get();
    
}

Then I tried by adding one more cin.get() and it worked

Code:

#include<iostream>

using namespace std;

int main()
{
    char a;
    int i;
    
    cout<<"hi";
    
    a=i=cin.get();
    
    cout<<a<<endl<<i;

    
    cin.get();
        
    cin.get();
}

Then I thought what value is this second last cin.get() is taking so I tried to save its value in another variable.

Code:

#include<iostream>

using namespace std;

int main()
{
    char a;
    int i,j;
    
    cout<<"hi";
    
    a=i=cin.get();
    
    cout<<a<<endl<<i;

    
    j=cin.get();
    cout<<endl<<j;
    
    cin.get();
}

\
And to my wonder it was always 10 which by ASCII convention means line feed. So can anyone guide me why is this last cin.get() is taking value automatically

And to my wonder it was always 10 which by ASCII convention means line feed. So can anyone guide me why is this last cin.get() is taking value automatically

Because it remains stranded in the input buffer.
If it is only one character, use

Code:

 cin.ignore();

to discard it.
And in situaions, where you're not sure how many left-overs are there,
use

Code:

cin.ignore(numeric_limits<int>::man(),'\n');

Thanks buddy .I really appreciate your concern and thank you again for helping me.
If you may, can you explain the cin.ignore or can you give me website referrence from where I can understand it better.
And the is the numeric_limit is any integer.
Regds
Xperience

Well.... as the name says.. it ignores !
Also, I just found out that there was two little errors in my previous post ...one being a typo
It should be...

Code:

cin.ignore(numeric_limits<streamsize>::max(), '\n');

[15] Input/output via <iostream> and <cstdio>, C++ FAQ

And numeric limits:
numeric_limits - C++ Reference
You could use any integer, but this way gives the maximum possible value.

Thank You