i have a problem:
when entering a char instead of an int as an input, the loop won't stop running.Code:int x=0; while(x!=6) { cout<<"in the loop"<<endl; cin>>x; }
How do I fix it? I want it to enter the loop normally, and ask me for a new input(like it does with any integer other than 6..).
Thanks!
You could just use a char instead.
When x is an int, cin>>x will only read an int from the input. If there is a char there, it'll do nothing (leaving the char there) and next time through the loop, the same char will still be there.... infinite loop.Code:char x; while (x != '6') ....
I'd just use a char, and convert it back to an integer at a later point if I need to.
thanksgood idea, i'll do it with a string though, cause inside the loop i have options and when getting an input of a char, 12 (for example) is just like 1.
If cin expects a number but is given something else, it switches into an error state. Any following input statements will fail without managing to consume any of the input, unless you correct the situation.
So in the general case
Code:int x=0; while(x!=6) { cout<<"in the loop"<<endl; if (!(cin>>x)) { cin.clear(); //reset the error state cin.ignore(1000, '\n'); //discard unsuitable input (just assuming they didn't type more than 1000 characters, consult FAQs for more correct ways) } }
I might be wrong.
Quoted more than 1000 times (I hope).Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
thx a lot
Last edited by ooopa; 11-19-2011 at 09:52 AM.
