Thread: Post Increment an Pre Increment operators in c++

Hi All,

i have small problem in understanding the post and pre increments in c++. Could you please help me in understanding how exactly the equation is executed. Below is the code:

Code:

#include <iostream>


using namespace std;


int main()
{
	int i=0,j=0;

	i =2;
	j =  ++i + i++ + i++ + i + ++i + i++;


	cout << " \nThe value of j is : " << j;

	return 0;
}

Originally Posted by laserlight

Yes. Read Stroustrup's answer to the FAQ: What's the value of i++ + i++? as it is applicable to your question.

Well the reference says, it is undefined. But how exactly the equation is executed? What is the value of "i" which is present in the middle of expression?

I got the answers for evaluation of "i", through operators precedence, but it was only half way and i'm lost after that...

my friends has derived some sort of assumed rules how the compilers gets the value and it applies correctly for all the permutational equations... but i need to know the exact procedure how it is executed.

Please do help me.. if you want i can describe the answer i got which is only half the solution.

Well the reference says, it is undefined. But how exactly the equation is executed?

it is undefined.

That means that it is undefined, you can never be sure how the compiler will evaluate the expression.

Jim