Thread: How can I add up how many ints are even in the same array??

I'v only started to learn c++ this year so maybe this is just a simple problem.

here is the question I was given:

Write a function of the form int countEvens(int[], int) that returns the number of even ints in a given array, when passed the array and the number of elements in the array. Remember the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.

countEvens({2, 1, 2, 3, 4},5) → 3
countEvens({2, 2, 0},3) → 3
countEvens({1, 3, 5},3) → 0

I passed the array and used the "mod" operator to identify which elements are even.

my problem is that I don't know how to add up how many even elements are in the array. Can anyone help me?

my code so far just displays which numbers in the array are even, I want to display how many are even. Here is my code

Code:

 
#include <cstdlib>
#include <iostream>

using namespace std;

int countEvens(int a[], int size)
{
    int i;
    
    for (i=0; i<size; i++)
    {
        if ((a[i]%2) == 0)
        {
           cout << a[i] << " is even" << endl;
        }   
    }   
    
}    



int main()
{
    int array[5] = {2,3,4,5,2};
    countEvens(array,5);
    
    system("PAUSE");
    return EXIT_SUCCESS;
}