hi.. this is my code:
Code:#include <iostream> using namespace std; int main() { float a,b; char ex[]="n"; do { cout<<"a=: " ; cin>>a; cout<<"b=: " ; cin>>b; cout<<"a/b= "<<a/b<<endl<<endl; cout<<"Stop? (y/n): "; cin>>ex; if (ex=="Y"||"y"){ return 0; } }while((ex!="y")||(ex!="Y")); }
I don't know what's wrong with this program..even I press n or N it exit..I want to repeat if I press n or N.
can someone help me?
Because this:Originally Posted by AndreyS10
Means:Code:if (ex=="Y"||"y"){
if ex=="Y" is true
OR
if "y" is true
"y" is not zero, so the second condition is always true.
Also, " and ' are different. "Y" indicates a string literal, and ex is a c-string, but you cannot compare one such string to another with ==. You can, however, compare single char values, but a char value is single quoted.
So perhaps you want something more like:
Code:char ex='n'; // single char instead of a c-string if (ex == 'Y' || ex == 'y'){ // single quotes around char values
C programming resources:
GNU C Function and Macro Index -- glibc reference manual
The C Book -- nice online learner guide
Current ISO draft standard
CCAN -- new CPAN like open source library repository
3 (different) GNU debugger tutorials: #1 -- #2 -- #3
cpwiki -- our wiki on sourceforge
thank you..I works..
I'm new to programming so I still learn.
