What's the output

[shivakumar]

#include<iostream.h> 
    int x = 10 ; 
    void main( ) 
    { 
         int x = 20; 
         ::x = x + ::x; 
         cout <<x; 
    }

[manasij7479]

Why don't you test yourself and find out ?
Did you forget that we're not compilers ?

ALSO
The program will fail to compile if you use a decent compiler.
(NOT the one from the stone ages that you're using)

It is
int main(), not void .
<iostream> instead of <iostream.h>
std::cout instead of cout. (or a using namespace std; statement)

[Ushakal]

First of all, it wont compile: it's std::cout (or you can put "using namespace std;" after the include) and you should be including <iostream>, not <iostream.h>.

I'm not going to tell you the output would be if it compiled, because it looks like this is homework or something and there's a policy about not handing out homework answers on this forum. Either deduce what the output should by taking into consideration the scope of each x variable, or get it to compile by fixing it.