C++ Novice help

**genesis531501** · 08-21-2011

I know the below code is riddled with errors. I am very new to C++ and I can run simple codes however this is my first time trying to do something this complicated. Well lets say complicated for me. Any help or suggestions are greatly appreciated.

Code:

# include <iostream>
# include <string>
# include <cmath>
# include <math.h>

using namespace std;


float PerformanceTE (float a, float b, float c, float T){
	  score = (a*(b-T)^c
		return score;
}

float Performancej (float a, float b, float c, float M){
	  score = (a*(M-b)^c
		return score;
}

float PerformanceTH (float a, float b, float c, float D){
	  score = (a*(D-b)^c
		return score;
}

int main ()
{

float a[10] {25.4347, 0.14354, 51.39, 0.8465, 1.53775, 5.74352, 12.91, 0.2797, 10.14, 0.03768};
float b[10] {18.00, 220.00, 1.50, 75.00, 82.00, 28.50, 4.00, 100.00, 7.00, 480.00};
float c[10] {1.81, 1.40, 1.05, 1.42, 1.81, 1.92, 1.10, 1.35, 1.08, 1.85};
float M;
float T;
float D;
float string score[10];
string name[5];
float 100m;
float Long jump;
float Shot put;
float High jump;
float 400M;
float time;
float sum;

cout<< " Welcome to the 2011 CSMC Decathlon"<< endl;
cout<< " Day 1"<< endl;
cout<< " Your first event will be the 100M dash"<<;
cout<< " Enter your 100M dash time"<<;
cin>> 100M;}
 T= 100m;

if (100M < 9.58)
{
	cout<< " That's a new world record!";
}
else
{
	cout<<" Your score is!"<< PerformanceTE = a[1]*(b[1]-T)^c[1];

	system("Pause");
}
return 0;
{

**manasij7479** · 08-21-2011

What do you mean by "I can run simple codes" ?

Programming has as much to do with 'running codes' as designing a hydraulic brake system has to with loading a garbage truck.

If this is something you've concocted on your own(as opposed to ^C + ^V), I'd suggest you to start from scratch again.

Keep the following points in mind:
1. INDENT PROPERLY.
2. Think about what you're doing, before 'doing'.
3. Start by coding small parts of it at a time.
4. The language has a syntax for a reason, not to haphazardly write whatever you want, like the following examples from your code.

Code:

score = (a*(b-T)^c

float c[10] {1.81, 1.40, 1.05, 1.42, 1.81, 1.92, 1.10, 1.35, 1.08, 1.85};
float High jump;
float 400M;
 //....
} return 0; {
//.....

**AndrewHunter** · 08-21-2011

Originally Posted by genesis531501

I know the below code is riddled with errors. I am very new to C++ and I can run simple codes however this is my first time trying to do something this complicated. Well lets say complicated for me. Any help or suggestions are greatly appreciated.

Yes, your code is riddled with errors. Try looking at what the compiler is giving you for errors and warnings, find the line number it is talking about, and then fix the problem. Once you do that repost your code with any unresolved errors or warnings and then ask a specific question. This board is not a syntax checking service.

**nimitzhunter** · 08-21-2011

Get familiar with assignment '='.

Code:

float c[10] = {1.81, 1.40, 1.05, 1.42, 1.81, 1.92, 1.10, 1.35, 1.08, 1.85};

That was one such instant in your code. now fix and figure out the rest.

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