Thread: Finding Letter Grade and Marital Status

I've not seen the syntax of the argument being used for cin.ignore, nor do I like to use defines, so I have to say that I am suspicious of that context. However, I can't say it won't work either.

I do know that you are using the switch statement incorrectly.

I would add iostream.h to your list of includes and you need a
return type for main(); should be int.

I would use a different flagging system for the loop to be more efficient. You don't want to print out a student score of -1.

Code:

#include <iostream.h>

int main()
{
  int TestScore, Grade; 
  char Name[15], marStat[15];
  char MarStat; 
  char continue = 'y';

  while(continue == 'y')
  {
    cout<<"\n Enter a Student's Name: "; 
    cin.getline(Name,15);
  
    cout<<" Enter Student's Test Score: "; 
    cin>>TestScore;
    cin.ignore(); 


    if(TestScore < 100 && TestScore >= 90"; 
      Grade=(char)'A' ; break; 
    else if (TestScore < 90 && TestScore >= 80"; 
      Grade=(char)'B' ; break; 
    //etc. 

    cout  << " Enter Student's Marital Status: "; 
    cin  >> MarStat;
    cin.ignore(); 

   switch(MarStat) 
  { 
     case 'M': case 'm': 
       strcpy(marStat, " Married ");
       break; 
     //etc
   } 

  cout<<"\n The Name of the Student: "<<Name; 
  cout<<"\n The Marital Status of the Student: "<< marStat; 
  cout<<"\n The Test Score of the student: "<<TestScore; 
  cout<<"\n The Letter Grade of the student: "<<Grade; 
  
  cout << "To stop at this time enter anything but y:" << end;
  cout << "To continue with another student enter y:" << endl;
  cin >> continue;
 } 
 
  char dummy;
  cin >> dummy;

  return 0; 
}