Thread: Help using cout to format how my statement is suppose to print

Ok first of all, my statement needs to print like this.

Code:

Second 0:
   Running: No Jobs
   Queue 0: Empty

It is a queue which is actually 3 arrays at the moment I just want to print wait[0]

like this

Code:

#include <iostream>
#include "queue.h"

using namespace std;

int main() {

 string jobname;
 int subtime, priority, runtime;
 int itemstoProccess=0;
 const int NUM_QUEUES = 4;
 const int MAX_RUNNING_TASKS = 2;
 const int MAX_INPUT_JOBS = 20;

 Queue wait[NUM_QUEUES];

 struct RUNNING {
  JOB job;
  int elapsed;
 } running[MAX_RUNNING_TASKS];

 struct INPUTJOBS {
  JOB job;
  int priority;
 } inputJobs[MAX_INPUT_JOBS];

 while(cin >> subtime>>jobname>> priority>> runtime)
 {
   inputJobs[subtime].job.jobName=jobname;
   inputJobs[subtime].job.runtime=runtime;
   inputJobs[subtime].priority=priority;
   itemstoProccess++;
 }//end while cin



 for( int sec=0; itemstoProccess!=0; sec++)
 {
   cout << "Second "<<sec<<":"<<endl;
   cout << "   Running: "; 

   if(running[0].job.jobName=="" && running[1].job.jobName=="")
   {
     cout << "No Jobs"<<endl;
   }
   cout << "   Queue 0: " << (wait[0].displayAll());
   

  //wait[0].displayAll();










itemstoProccess--;

 }// end sec for loop


} // end main

my displayAll() function is written like this.

Code:

void Queue::displayAll()
{
  if (isEmpty()) cout << "Empty." << endl;
  QueueNode *temp = frontPtr;

  while (temp!= NULL) 
  {
    cout << temp->item.jobName;
    temp = temp->next;
  }
} // end display

I get this error message:
error: no match for 'operator<<' in 'std:perator<< [with _Traits = std::char_traits<char>](((std::basic_ostream
<char, std::char_traits<char> >&)(& std::cout)), ((const char*)" Queue 0: ")) << wait[0].Queue::displayAll()'

thanks for looking