Thread: pseudo-random number generator problem

Hi guys im trying to make my own pseudo-random number generator from the algorithm below using the kent chaotic map.

Code:

       
             { x(n)/m,  0 < x(n) <=m
x(n+1)= {
             {(1-x(n))/1-m,  m<x(n) <1

where 0<m<1 (m could be 0.7 for example and all other variables could be anything)

I've tried playing around with loops for example but cant get it working:

Code:

#include <iostream>

int main (int argc, char * const argv[])
{
   	double m = 0.7;
	double x[10];
	double k = 10;
	int n, Chaotic_map;
{	
	for (n=0;n<k;n++)
		x[n]+1=x[n]/m;
	
	for (m<x[n]<1)
		Chaotic_map= x[n]+1=(1-x[n])/(1-m);
	printf("%d", Chaotic_map);
	 
    return 0;
}

But im still lost, Any ideas??

If you remember that the right side of a piecewise-defined function should have the word "if" in it, then you're golden:

Code:

if x[n] <= m then
    x[n+1] := x[n]/m
else
    x[n+1] := (1-x[n])/(1-m)