Thread: default intialization of an array

If you want to make things clear, write something along these lines:

Code:

#include <iostream>
#include <cstdlib>

using namespace std;

const int C = 5;
char str[C];

int main()
{
    cout << '"';
    for (int i = 0; i < C; ++i)
    {
        cout << str[i];
    }
    cout << '"' << endl;

    for (int i = 0; i < C; ++i)
    {
        cout << static_cast<int>(str[i]);
    }
    cout << endl;

    cout << static_cast<int>(' ') << endl;

    system("pause");
    return 0;
}

Originally Posted by laserlight

If you want to make things clear, write something along these lines:

Code:

#include <iostream>
#include <cstdlib>

using namespace std;

const int C = 5;
char str[C];

int main()
{
    cout << '"';
    for (int i = 0; i < C; ++i)
    {
        cout << str[i];
    }
    cout << '"' << endl;

    for (int i = 0; i < C; ++i)
    {
        cout << static_cast<int>(str[i]);
    }
    cout << endl;

    cout << static_cast<int>(' ') << endl;

    system("pause");
    return 0;
}

Thanks a lot for the code, laserlight. It was helpful.

First let me clear this out. The int 0, NULL character '\0', and character '0' are different from each other. Correct?

Anything which has been declared globally is initialized to zero, so every element of str[C] in your code is 0. Then, why doesn't cout'ing produces a series of 0's instead of spaces. Do you get me?