Thread: passing arguments by reference - finding integer and fraction parts

Because there are numbers that fit in a float that don't fit in a long.

Originally Posted by jackson6612

Are you alluding to the fact that long has a wide range? But the purpose is to find the integer part so simple declaration int would do. Strictly, "2.0" is not an integer. Please guide me. Thanks.

You started so well, and then ... you do know what the word "wide" means, right?

Anyway, as an example, you could use 1.12e17.

Originally Posted by jackson6612

Thanks, tabstop, and sorry for asking this again.

But don't you think using int& wouldn't hurt that much? Please let me know. Thanks.

Run the following to see the point:

Code:

#include <iostream>

int main() {
    float foo = 1.12e17;
    long bar = foo;
    std::cout << foo << " " << bar << " " << std::endl;
    return 0;
}