Pass pointer to overloaded operator

[Sevko]

I have an example here:

#include <iostream>

class test{
    private:
        int a;
    public:
        test(){a=3;};
        test operator+(whatgoesinhere? x){test temp;temp.a=a+variable a that we got from b;return temp;}
};

using namespace std;

int main()
{
    test *a = new test, *b = new test;
    a=a+b;//call to the function should look like this but with the correct prefixes so the return gets into a
    return 0;
}

[kmdv]

The question is? You pass pointers to operator +. The operands should be of 'test' type not 'test*'.

test operator + (const test& a)
...
test a;
test b;
a = a + b;

[Sevko]

You sure helped me a lot... If I were to use testa a, b and not their pointers with allocated memory then i'd just have a test x in the arguments...
Can some one answer me what I've asked no amtter how stupid or illogical it is, basicly my question is how do you pass a pointer with allocated memory to a function, in this example the class to the operator +.

[kmdv]

*a = *a + *b; // pointer dereference

Don't forget to release (delete) memory.

[Sevko]

Thank you.