Thread: I need help with two parallel arrays

  1. #1
    Registered User
    Join Date
    Apr 2011

    I need help with two parallel arrays

    I'm suppose to write a program that uses two parallel arrays to store student names and their grades. It should use an array of strings that hold the names and and array of integers that hold the grades. The program should produce a report that displays list of students names and grades, and the name of the student that has the highest grade. The names and grades should be stored using an initialization list at the time the arrays are created. Use a loop and conditional statement to determine which student has the highest grade.

    This is what I have tried so far. I'm new at this and there not many good examples in the book

    #include "stdafx.h"
    #include <iostream>
    #include <iomanip>
    #include <string>
    using namespace std;
    int _tmain(int argc, _TCHAR* argv[])
    	int i = 0, h = 0, saved = 0;
    	int g[ ] = {87, 99, 70, 75, 77, 91, 95};
    	string s [ ]= {"S1", "S2", "S3", "S4", "S5", "S6", "S7"};
    	while ( i <= 3)
    	{if (g[i] > h)
    	{h = g[i];
    	  saved = i;
    	cout << "Highest " << h;
    	cout << "student is " << s[saved];
    	return 0;

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    > while ( i <= 3)
    You need a for loop, to examine each element of the array.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Hurry Slowly vart's Avatar
    Join Date
    Oct 2006
    Rishon LeZion, Israel
    while ( i <= 3)
    where do you get this 3 stuff?

    in general loop for all array members will look like

    for(i=0; i < sizeof(g)/sizeof(g[0]); i++)
    after that - your finding highest score alg should work fine

    and what left - is to use another loop to print all students (or even the same loop)
    All problems in computer science can be solved by another level of indirection,
    except for the problem of too many layers of indirection.
    David J. Wheeler

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