How do you print decimal numbers that are have more then 6 didgets? I'm writing a small prog to find the square root of 50 but the decimals are large and it only prints out 6 spots. any idea what could remedy the situation? (Code is below)
Code:#include <math> #include <iostream> double i = (double)sqrt(50.0) ; main (){ cout << "square root of 50 :" << i ; }
Last edited by Isometric; 03-20-2002 at 04:33 PM.
"Christ died for our sins. Dare we make his martyrdom meaningless by not committing them?"
You could try -
Code:#include <cmath> #include <iostream> #include <iomanip> using namespace std; int main (){ double i = sqrt(50.0) ; cout << setprecision(10) << "square root of 50 :" << i ; return 0; }
#include <math.h>
#include <iostream.h>
#include<conio.h>
float i = (float)sqrt(50.0) ;
main (){
cout << "square root of 50 :" << i ;
getche();
}
This gives me a result of 7.07107
Is that what you are looking for?
-Colin
Sorensen has the right idea. I would add the following:
Code:#include <cmath> #include <iostream> #include <iomanip> using namespace std; int main () { double i = sqrt(50.0) ; cout << setprecision(10) << setiosflags(ios::fixed | ios::showpoint) << "square root of 50: " << i ; return 0; }
Please explain this line? what is setprecision and setiosflags?Originally posted by biosx
Code:cout << setprecision(10) << setiosflags(ios::fixed | ios::showpoint) << "square root of 50: " << i ; }
Also Colin that is what I'm getting now but there is really alot or didgets. That squared is 50.0000309449. The real number will be 5 squareroots of 2 but I want a decimal number for it.
"Christ died for our sins. Dare we make his martyrdom meaningless by not committing them?"
Download a package called NTL. It is a C++ package that allows abitrary precision math. You can find it through any search engine.
