Thread: non-const argument and const pointer

>> I have a C function ... which I know that doesn't modify x.
This is one the reasons const_casts<> exists.

If you must, you could create a full copy of the double and use that:

Code:

double x = *A.get_ptr();
double *qx = &x;

gg

Originally Posted by nepper271

Hello all,

I have a C function

Code:

void foo (double * x, size_t s);

where x is a vector and which I know that doesn't modify x.

And I have a pointer

Code:

const double * px = A.get_ptr ();

Is there a way to pass px to foo, without using const_cast, i.e. other than

Code:

double * qx = const_cast < double * > (px);

?

Thanks

why don't you use constant parameter if you know x won't be modified?

Code:

void foo( const double * x, size_t s);

Originally Posted by nepper271

foo is not my function, is part of a C library.

Oh. my bad.