Thread: can't figure out simple program

hi, can someone please tell me why this won't compile? errors are improper typedef 'test', statment mising ; and expression syntax. thanks so much

Code:

#include <iostream.h>
#define tab '\t'

struct test{
		char name;
		int value;
		};	

ostream& operator<<(ostream& oput, test& t)
{
	oput<<t.name<<tab;
	oput<<t.value<<tab<<endl;
	return(oput);
};

main()
{
	test try={"a",1};
	cout<<try;
	return(0);
}

I dunno about that

A simple error blight, but somewhat easy to miss if you don't know C++ style try..throw..catch exception handling.

try is a keyword.

It is the same problem you would have with a variable called for or do.

Also, a smaller but critical error, when you define an overloaded operator you are defining a function. So don't put a semicolon after the declaration.

One last error, you are assigning "a" (which is a const char*) to a variable of type char without a cast. You will need to change the quotes to single quotes.

So:

1: Change try to something else
2: No semicolon after operator<< declaration
3: Single quotes around the a

thanks, as you can see i'm new at this . . . i was taught to put the ; after overloads, it works either way so i was wondering why it's a critical error? thanks again