We are doing a homework practicing our ability to write our own functions.

I need to find the order of magnitude of numbers inputted. According to the instructor, the OoM(50) = 1, OoM(100) = 2, OoM(3250)= 3, and so on.

So essentially, its scientific notation. 50 = 5.0 x 10^1

I cannot think of a way to code for this... I mean is it the 10th root of each number?

Hell, I know how to find the OoM on my own, I know how to write a damn function, but I can't figure out a way to solve this

Here's what I have coded so far:

Code:

#include <cstdlib>
#include <iostream>
#include <cmath>
using namespace std;
int OoM(double number);
/*takes a number inputted by the user and gives the user that number's order
of magnitude*/
int main(int argc, char *argv[])
{
double input_number;
int result; //result will be the OoM of the number input
cout << "Enter a number to find out it's order of magnitude:" << endl;
cin >> input_number;
result = OoM(input_number);
cout << "The order of magnitude of " << input_number << " is:" << endl;
cout << result << endl;
system("PAUSE");
return 0;
}
int OoM(double number)
{
return (pow(number,(1/10)));
// takes a user input number and takes the 10th root
// returning this in int form gives us the OoM. Compiler gives warning
// however we WANT this conversion of double to int because the OoM is always
// an integer. The number you may be trying to find the OoM of could be of
//type double, but it's OoM is always an int.
}

Any help would be appreciated.