Thread: Initializing arrays to zero all in one go?

Originally Posted by kmdv

Memset works byte-by-byte (rather, dword-by-dword or qword-by-qword respectively) and this is why it is _faster_. Of course, the assignment operator can work as memset either, but this is a different story.

Ah, you're right, dword-by-dword or qword-by-qword indeed, it's faster. However, I think that we should rely on the fact that our compiler produces fast code for those operators (and it probably does).

edit:

Personally, I don't feel any need for memset (except raw buffer 0-ing).

Exactly, that's what I use it for.