Hi
Please take a look at this non-compilable example:
This will only compile if I replace the pointer *b with a reference. In my book it says that the reason why that is the case is because "&asd++ is inherently ambigous", but explains it no further.Code:#include <iostream.h> class test{ public: int a; friend operator++(test *b); }; operator++(test *b) { b->a=b->a+1; } int main() { test asd; asd.a=1; &asd++; return 0; }
What does the author mean by that?
Best,
Niles.