Thread: if/ else if will not return else if when it is true

I have a code which creates a random number, the user has to guess it in 10 tries. The first cout is the option to "Cheat? (Y/N)" which will display the secret number (the random number), mostly just for me to see whats happening.

If the user selects Y the number is displayed. But also it will be displayed if they select N. This is one point of confusion.

After this they are prompted to enter a guess. If the guess is wrong they will be asked if they want to try again. Whether they say Y or N, the program just quits and outputs nothing.

Here is the code:

Code:

#include <stdlib.h>
#include <iostream>
#include <cstdlib>
#include <time.h>
using namespace std;

int main() 
{ 
	srand ( time(NULL) );
	int number = (rand() % 15) + 1;
	int guess; 
	int trycount = 0;
	char choice;
	cout << "Cheat? (Y/N) \n";
	cin >> choice;
	if (choice == 'Y' || 'y')
		cout << "The secret number is " << number << ".\n";
	else if (choice == 'N')
		cout << "Good for you.";

	cout << "Please enter a guess: ";
	cin >> guess;
	while (guess != number && trycount < 10) 
		{
			int choice;
			cout << "Wrong, guess again? (Y/N): ";
			cin >> choice;
			if (choice == 'Y')
			{
				cout << "Guess again: ";
				cin >> guess;
			}
			else if (choice != 'Y')
				break;
			{
			if (guess < number) 
				cout << "Too low \n";
			else if (guess > number)
				cout << "Too high \n";
			else (guess == number);
				cout << "You guessed the number!";
			}
			trycount++; 
		} 
return 0;
}

Here are some outputs/inputs:

Cheat? (Y/N)
Y
The secret number is 13.
Please enter a guess: 6
Wrong, guess again? (Y/N): Y

The Debugger has exited with status 0.

----------

Cheat? (Y/N)
N
The secret number is 11.
Please enter a guess: 7
Wrong, guess again? (Y/N): N

The Debugger has exited with status 0.

Can anyone give me a hint about what I am missing? I feel like it is a simple solution but I've tried it for a bit and I can't seem to figure out what is going wrong. Thank you!