Thread: strdup

Hi,

An exercise from my book is to implement my own version of the strdup function, which returns a copy of a string allocated on the freestore.

This is my code:

Code:

char *strdup(const char* ch)
{
	const char* p = ch;
	int size = 0;
	while(*p){
		++size;
		++p;
	}

	int index = 0;
	char* name = new char[size];
	while(*ch){
		name[index] = *ch;
		cout << *ch;
		++ch;
		++index;
		
	}

	return name;
		
}

My question is that when I create name, I allocate memory on the free store. When I return this, I take it that it is still allocated on the freestore and when whatever has called it finishes using it, that is when I call delete[]? Is that correct?

BTW, the exercise states that I cannot use any standard library function, hence my own version of size.

Thanks.

Originally Posted by Salem

Looks good to me - your analysis is correct.

Thanks, I'm on the right track then!