Thread: Why would they use this segment instead of this one?

Why use this segment

Code:

#include <iostream>
using namespace std;

int main ()
{
  int numbers[5];
  int * p;
  p = numbers;  *p = 10;
  p++;  *p = 20;
  p = &numbers[2];  *p = 30;
  p = numbers + 3;  *p = 40;
  p = numbers;  *(p+4) = 50;
  for (int n=0; n<5; n++)
    cout << numbers[n] << ", ";
  return 0;
}

instead of this segment?

Code:

#include <iostream>
using namespace std;

int main ()
{
  int a[5];
  int *b;
  b = a;  *b = 10;
  b = a;  *(b+1) = 20;
  b = a;  *(b+2) = 30;
  b = a;  *(b+3) = 40;
  b = a;  *(b+4) = 50;
  for (int n=0; n<6; n++)
    cout << a[n] << ", ";
  return 0;
}

Does the first, seemingly more complicated block do something more than the second block? Even though both print the same thing?

NOTE in the first block, p is equivalent to b in the second block. and "numbers" is equivalent to a.