Thread: Arrays of pointers...

For the record, here is the code that works with an array of char pointers (now free of all bugs -- I hope):

Code:

#include <iostream>
#include <string>

using namespace std;

struct stringStruct {
    stringStruct() : arrayOfPointers(NULL) { initialize(); }
    void initialize();
    string* str;
    string* anotherStr;
    const char** arrayOfPointers;
};

void stringStruct::initialize() {
    str = NULL;
    anotherStr = NULL;
}

void doStuff();

int main() {
  doStuff();
  cout<< "\nHaha, you got to press Enter."<<endl;
  cin.get();
  return 0;
}

void doStuff() {
  stringStruct object;
  object.str = new string;
  *object.str = "Yes, a string...\n";
  *object.str += "Yes, another string...\n";
  *object.str += "Yes, even another string...\n";
  int sizeOfStr = object.str->size();
  object.anotherStr = new string;
  int sizeOfArrayOfPointers = 3;
  object.arrayOfPointers = new const char*[sizeOfArrayOfPointers];
  int i2 = 0;
  for (int i = 0; i < sizeOfStr; i++) {
    if (object.anotherStr == NULL) {
        object.anotherStr = new string;
    }

    if (object.str->at(i2) == '\n') { //we're at a new-line character
        i2++; //increment so as to skip the new-line character to the next character, which wont be a new-line character
    }

    if (i == sizeOfArrayOfPointers - 1) { //we're at the last element of the array of pointers
        //continue looping through object.str...
        while (object.str->at(i2) != '\n') {
            *object.anotherStr += object.str->at(i2);
            i2++;
        }
        object.arrayOfPointers[i] = object.anotherStr->data();
        for (int i = 0; i < sizeOfArrayOfPointers; i++) {
            cout<< object.arrayOfPointers[i] <<endl;
        }
        
        if (object.arrayOfPointers) {
          delete [] object.arrayOfPointers;
        }

        if (object.anotherStr) {
          delete object.anotherStr;
          object.anotherStr = NULL;
        }
        
        return; //out of the function
    }

    while (object.str->at(i2) != '\n') { //iterate till the next new-line character
      *object.anotherStr += object.str->at(i2); //add characters to the "anotherStr"
      i2++;
    }

    object.arrayOfPointers[i] = object.anotherStr->data();
    object.anotherStr = NULL; //reset this pointer
  }

}

And here is the code with the vector that I ended up using in place of the array of pointers:

Code:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main() {
  string *str = new string;
  *str = "Yes, a string...\n";
  *str += "Yes, another string...\n";
  *str += "Yes, even another string...\n";
  string* anotherStr = new string;
  int sizeOfStr = str->size();
  vector <string> aVectorOfStrings; //create a vector for storing individual strings
  int i2 = 0;
  for (int i = 0; i < sizeOfStr; i++) {
    if (anotherStr == NULL) {
      anotherStr = new string;
    }

    if (str->at(i2) == '\n') {
      i2++; //skip past the new-line character
    }

    while (str->at(i2) != '\n') { //read up until the next new-line character
      *anotherStr += str->at(i2); //add characters to the string
      i2++;
    }
    aVectorOfStrings.push_back(*anotherStr); //add a new string to the vector of strings
    delete anotherStr;
    anotherStr = NULL; //reset the pointer

    if (i == 2) { //we just added the last string to the vector...
        break; //out of the loop
    }
  }

  int sizeOfVector = aVectorOfStrings.size();
  for (int i = 0; i < sizeOfVector; i++) {
    cout<< aVectorOfStrings.at(i) <<endl;
  }

  cout<< "\nHaha, you got to press Enter..."<<endl;
  cin.get(); //make the user press enter
  return 0;
}

Both work as expected, but the vector method is obviously preferred.