Thread: Polish form headache...

  1. #1
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    Polish form headache...

    This will be the last question concerning my program.. So the user inputs a string like:

    this + that + anotherOne - justoneMore

    where this, that etc are classes containing a name and a vector of integers. How could I create another class which will hold the result? (The result will be a class with a vector whose elements are being added or substracting).

    I got the names in a string vector and the operands in a char vector as well. I made a loop, but it works like this: it add this with that, then that with another one, and then it adds the two results...

    I would appreciate a code.. at least for a simpler thing, such as a + b - c, where a , b, c are integers..

  2. #2
    and the Hat of Guessing tabstop's Avatar
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    Why would you want a class for the result? Isn't the result just an int?

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    No, it's a class with a vector in which I store the sumation or the difference of the components.

  4. #4
    and the Hat of Guessing tabstop's Avatar
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    If this, that, etc are objects, then the result is the same type of object as this, that, etc. And presumably you would define operator+ and operator- on those objects to add or subtract element-by-element.

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    I did that.... I even overloaded += so that I can have a temp class which does
    Code:
     temp += this + that
    . then it keeps adding.. but id does not add correctly..

  6. #6
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by Veneficvs View Post
    I did that.... I even overloaded += so that I can have a temp class which does
    Code:
     temp += this + that
    . then it keeps adding.. but id does not add correctly..
    Then you didn't do it right. Actually, temp += this + that is almost certainly wrong, unless you initialized temp to start with. But without actual code goodness, we're just flailing here.

  7. #7
    The larch
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    What on earth are you talking about? o_O

    Make a class overloading operator= and providing a constructor for conversion from this + that + anotherOne - justOneMore?
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

  8. #8
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    Quote Originally Posted by anon View Post
    What on earth are you talking about? o_O

    Make a class overloading operator= and providing a constructor for conversion from this + that + anotherOne - justOneMore?
    I will translate the code and post it here... I am too tired and freaking nervous now.... good night.

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    Here is the code
    Code:
         CArray temp, first, second;
        for(contor = 0; contor < (int)simbols.size(); contor++)
        {
            if(simbols[contor] == '+')
            {
                for(i = 0; i < (int)arrays.size(); i++)
                {
                    if(arrays[i].name == operations[contor])
                    {
                        first = arrays[i];
                    }
                    if(arrays[i].name == operations[contor + 1])
                    {
                        second = arrays[i];
                    }
                }
                temp += (first + second);
            }
            if(simbols[contor] == '-')
            {
                temp += (first - second);
            }
        }
    Consider the following input line:
    first + second - third
    Ok. Arrays is a vector of type CArray, which contains the name of the array and a vector of type int, for the components. Operations is a string vector containing first, second, third and any other array that might appear in the line. Simbols is a string vector that contains + and - in the order they appear in the input line. Temp is going to retain the result of those sumations or differences.

    I am adding the arrays two by two ... but it acts like this: 1 + 2 + 3 should be 6... but it does 1+ 2, then 2 + 3, and then 1 + 2 + 2 + 3 , which is 8... So how could I properly adjust the loop to calculate what I want, please?..

  10. #10
    and the Hat of Guessing tabstop's Avatar
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    As I stated above, temp += (first + second) is grossly incorrect. temp = first. temp += second. temp -= third.

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    Quote Originally Posted by tabstop View Post
    As I stated above, temp += (first + second) is grossly incorrect. temp = first. temp += second. temp -= third.
    Thanks a lot! Does it work for any number of arrays?

    Edit: Doing what you said gives me a debug error.. could you modify it on my code, please?
    Last edited by Veneficvs; 05-09-2010 at 05:49 AM.

  12. #12
    and the Hat of Guessing tabstop's Avatar
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    If operator is plus, you should have "temp += second", and if operator is minus, you should have "temp -= second". Also, and this is big, you don't ever bother to initialize first and/or second in your '-' case. You'll need to walk through arrays just the same in '-' as you do in '+'.

  13. #13
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    Quote Originally Posted by tabstop View Post
    If operator is plus, you should have "temp += second", and if operator is minus, you should have "temp -= second". Also, and this is big, you don't ever bother to initialize first and/or second in your '-' case. You'll need to walk through arrays just the same in '-' as you do in '+'.
    I didn't do it because I tested with pluses. And it did not work for them..

    Edit... I found the problem... it seems that contor runs out of dimension.
    Last edited by Veneficvs; 05-09-2010 at 06:02 AM.

  14. #14
    and the Hat of Guessing tabstop's Avatar
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    Quote Originally Posted by Veneficvs View Post
    I didn't do it because I tested with pluses. And it did not work for them..
    What "doesn't work" about it?

  15. #15
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    Quote Originally Posted by tabstop View Post
    What "doesn't work" about it?
    Still doesn't work. If I say
    ALpha: 2 2 2 2 2
    Beta: 3 3 3 3 3
    Teta: 4 4 4 4 4

    And then Alpha + Beta + TEta it gives me:
    1 1 1 1 1.

    Edit: corrected with temp += treia... but for more than 3 operands it still gives bad results... this cannot be solved in a loop I am afraid.. I think Polish form could do it.
    Last edited by Veneficvs; 05-09-2010 at 06:19 AM.

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