Thread: Variable Declaration

If i declare buf[32] in function(), it means it will be redeclared everytime i call the function?
In this case would it be better to declare it globally?

Code:

void function()
{
    char buf[32] ="Hello";
    cout<<buf<<endl;
}

int main()
{
    for(int i)0;i<10;i++) function();
    return 0;
}

Originally Posted by Ducky

If i declare buf[32] in function(), it means it will be redeclared everytime i call the function?

Yes.

In this case would it be better to declare it globally?

Not unless it's a bottleneck.
Although you could make it static. Then it would only be created and initialized once and still only be visible from inside the function.

Thanks for the explanation.

Do you mean static global or like this?
Also static would mean that i couldnt change its value, right?

Code:

void function()
{
    static char buf[32] ="Hello";
    cout<<buf<<endl;
}

Like you have it is good, I think, depending on what you want done with it. Leaving it as static does not mean you would be unable to change the value, simply that the array would only be created/initialized once and any changes that were made in between instances of the function being called would remain in place from instance to instance.

Thank you hk_mp5kpdw!

Generally you shouldn't worry about this at all. In this case the call to cout will most likely take 99% of the time spent in this function.

Creating the array pretty much means instructions to store the string "hello" in a block of memory. In this case it needn't be more expensive than assigning two integers ("hell" and "o\0").