Don't worry so much about the thread-safety. I know what I'm doing there, and things will be thread-safe. I'm a semi-competent programmer who went on a bit of a hiatus so things are a bit rusty.
So it turns out my example wasn't exactly as I remembered it (just took a look at the code again) and what I'm trying isn't compiling. So let's try this again...
Again doesn't compile. What's the general "rule" here to indicate to the compiler a lack of infinite recursion.Code:#include <iostream> class A; class B { public: void setA1(int A1); void copy(void); void print(void); private: A a1, a2; }; class A { public: friend void B::copy(void); friend void B::setA1(int A1); friend void B::print(void); private: int _a; }; void B::setA1(int A1) { a1._a = A1; } void B::copy(void) { a2._a = a1._a; } void B::print(void) { std::cout<<a1._a<<" "<<a2._a<<std::endl; } int main(void){ B b; b.setA1(5); b.copy(); b.print(); std::cin.get(); return 0; }
Originally Posted by golfinguy4
