Thread: problems with nesting in looping

ok so i am told to do a problem where i am using a loop to displaying ASCII characters for codes 0-127 displaying 16 on each line. but when I put it in my program and try and run it, my comp starts beeping at me and the output is repetative can someone help me please... thank you

One of the ASCII characters is "beep". If you're getting things repeated, then you should check how you structure your loop (i.e., make sure you don't start each loop at 1, since that means you'll never get past 16).

Im not sure what you extactly mean with starting the loop at 1 did i do that here? because it is still repeating

Code:

#include<iostream>
using namespace std;

int main()
{
	char dec = 0;

 
	while(dec <= 127)
	{
		cout<< dec
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++
			<< " " << dec++ 
			<< " " << dec++
			<< " " << dec++ << endl;
		while ( dec == 122 || dec >= 127)
		{
			cout<< dec
				<< " " << dec++
				<< " " << dec++
				<< " " << dec++
				<< " " << dec++
				<< " " << dec++ <<endl;
		break;
		}

	}
		system ("pause");
		return 0;
}

So when your compiler says:

Code:

ascii.cpp:9: warning: comparison is always true due to limited range of data type

that might give you a hint. (Also hint: you should see the thread about signed vs. unsigned char in the C forum.)

im not trying to ask for you to just give me the answer but I dont know what you mean? my compiler doesn't say that. but should I try and meybe enter a bool or and if statement to make it stop repeating?

Originally Posted by wobbles

im not trying to ask for you to just give me the answer but I dont know what you mean? my compiler doesn't say that. but should I try and meybe enter a bool or and if statement to make it stop repeating?

Then you should either (1) get a better compiler or (2) stop muffling your compiler's warnings. Which one is appropriate depends on what compiler you have and what you've done to it. But it means just what it says: for any variable of type char, that variable will always be less than or equal to 127 (on my system and presumably your system as well). It is therefore not possible for your loop to stop, since any variable of type char will be less than 127. Try the following and see what you get:

Code:

#include <iostream>

int main() {
    char bob = 127;
    bob = bob + 1;
    std::cout << (int) bob << std::endl; //cast to int, so the value is printed instead of a character
    return 0;
}

You could, simply, make an int to check how far you are on the line, and the usual one to check how far along the 127 characters you need to display

Then once the counter reachs sixteen you insert a line break, and one you reach the 127^th character you "return" to stop the program.

thank you to those who tried to help me.. I appreciate it greatly but im still not quite getting it, I was also reading somewhere about doing it ++dec to get to not keep going to the negative side of it and continuing to loop, am I on the right track?

here is what I have so far

Code:

#include <iostream>
using namespace std;

int main()
{
	char dec = 0;
	char cha = 0;


	cout << "Here are the ASCII codes from 0 to 127\n";
	cout << "---------------------------------------\n";
 
 
	for(dec = 0; dec <= 127; ++dec)
	{
		for (cha = 0; cha = 16; ++cha)
		cout << dec << "\t";
			
		cout << endl;
		

	}
		return 0;
}

and still everytime I ouput it I get a repatative answer and its even the wrong symbols. how can i fix this can some one please help thank you.

ok so now I have it so it stops and doesnt repeat but now it doenst show any characters is there something im missing?

Code:

                                       for (int i = 0; i <= 127; ++i)
		{
			for (int j = 0; j == 16; ++j)
				cout << (j * i) + j<< "\t";
				cout << endl;
					
		}
		
return 0;
}