Thread: counting # of digits

Hello,

I have been trying to count the number of digits in an integer. I know I am close, but I am not quite sure what I am doing wrong. Could someone please point me in the right direction?

Code:

using namespace std;
int main()
{
  long A;
  long B;
  int n=0;

  cout << "enter value: " ;
  cin >> A;
  cin.ignore();

    if (1000000000 < A >= 0) {
    ++n;    
    (A /= 10);
    cout << A << " is " << n << " digits long" << endl;
    }


}

My output is always 1 for A. I know I am just misunderstanding something simple.

Thank you in advance for any help on this problem.

I think I just got it.

Code:

#include <iostream.h>
#include <windows.h>
#include <ctype.h>

using namespace std;
int main()
{
  long A;
  long int
  long B;
  int n=0;

  cout << "enter value: " ;
  cin >> A;
  cin.ignore();
  int C = A;
    do {
    ++n;
    A /= 10 ;
    }
    while (A!=0)
    ;
    cout << C << " is " << n << " digits" << endl;
return n;
}

Thanks for the feedback though, and the wtf part was lack of sleep while messing with this. I didn't realize I had left that in the posted code.