Assembler - binary

[subdene]

Can anyone help me out with this, b v.greatful. I'm trying to convert a given int to a binary number. I can output the data by dividing the num by 2 each time, e.g
10/2 = 0
5/2 = 1
2/2 = 0
1/2 =1
Program outputs 0101, but this has to be revesed so 1010. any ideas? Please!!!

void DecBinary(short int Num1)
{
short int Temp,Answer=0;

asm
{
mov ax,Num1;
mov Temp,ax;
Binary:
mov Answer,0;
mov bx,2;
xor ax,ax;
mov ax,Temp;
div bl;
mov bl,al //get whole no out of al
mov Temp,bx;

cmp ah,0;
jz NotNum;
jmp Next;

NotNum:
inc Answer;
}

asm
{
Next:
}

cout << Answer;

asm
{
cmp Temp,0;
jne Binary;
}
}

[Unregistered]

you could use push/pop to push the # on stack and then pop the # off when you need to. The would display in opposite order...that is just one way to do it

[Sorensen]

An example -

#include <cstdio> 
using namespace std;

int main()
{
	int i = 123;
	char* form = "%d";
	_asm
	{
		mov eax,i
		mov ecx,32
bin:		
                mov ebx,eax
		and ebx,0x00000001
		push ebx
		shr eax,1
                loop bin
		mov ecx,32
print:	
		pop eax
		mov ebx,form
		push ecx
		push eax
		push ebx
		call printf
		add esp,8
		pop ecx
		loop print        
     }

	return 0;
}

[subdene]

Thanks for everyones help. Tried push and pop, works on win98 my system, but crashes on an nt system. can't understand why???
Anyway cheers.

[Nor]

What language is that (Assembly) and where can i read up on it?
I see it when I use my debug program.

[golfinguy4]

Read this. It's pretty good. But, you have to come here to get it cause it is over the limit for a file size. http://www.flashdaddee.com/forums/sh...&threadid=1235

[Nor]

thx