Thread: How to draw shapes with only for loops?

Ok I have this problem.

First I need to make a right triangle:

#
##
###

Done.

Then I need to make an opposite right triangle:

- #
-##
###

(I hope you know what I mean. Not any isosceles triangle, just the same triangle but the opposite.)

Not done.

Here is the code I used for the first one:

Code:

	for (int row = 0; row < 10; row++)
	{
		for (int col = 0; col <= row; col++)
		{
			cout << "#";
		}
		cout << "\n";
	}

For the second one my code was this, but the problem is that I can't use the int count = row - 2, and the if statement that goes along with it. I can only use another for loop.

Code:

for (int row = 0; row > 3; row++)
	{
		int count = row - 2;
		for (int col = 0; col > 3; col++)
		{
			count ++;
			if ( count - 1 == 0 )
			{
				cout << "#";
			}
			else {cout << " ";}
		}
		cout << "\n";
	}

Can anyone help me with this? I need another for loop added to the original code for the first right triangle.

So you need a loop to print the spaces (and you already calculated how many spaces you need, it looks like).

Yea. Right now what I would like to know is how do I make the right triangle flip upside down? So that there will be 9 '-" on the first line, 8 on the second, 7 on the third, etc. Then at the end of each line after all the '-', there will be a '#', so on the first line there will be 1 of them, then 2, then 3 etc.

So that way I can make my opposite right triangle.

See if you take this code and run it you will see the dashes and the #'s. I need to know how to flip the dashes upside down, and the #'s flip them to the side, so the #'s will form my opposite right triangle.

Code:

for (int row = 0; row < 10; row++)
	{
		for (int col = 0; col <= row; col++)
		{
			cout << "-";
		}
		
		
		for (int lol = 0; lol < row + 1; lol++)
		{
			cout << "#";
		}
		
		
		cout << "\n";
	}

Originally Posted by CplusplusNewb

See if you take this code and run it you will see the dashes and the #'s. I need to know how to flip the dashes upside down, and the #'s flip them to the side, so the #'s will form my opposite right triangle.

The answer to that is to think for seven seconds. In the first row, how many dashes do you want to print? 9? Then why oh why stop your loop at 0? That doesn't make any sense.

Well I'm only a beginner, what you jsut said will actually take me like 5 trial and errors. >.>

Code:

for (int row = 9; row < 10; row++)
	{
		for (int col = 0; col <= row - 1; col++)
		{
			cout << "-";
		}
		
		
		for (int lol = 0; lol <= 9 - row; lol++)
		{
			cout << "#";
		}
		
		
		cout << "\n";
	}

Ok for this one it outputs

---------#

9 dashes and 1 #.

What should I change so that as the number of dashes decreases by 1, the number of #'s increases by 1?

Originally Posted by CplusplusNewb

[code]

What should I change so that as the number of dashes decreases by 1, the number of #'s increases by 1?

Nothing? That will happen as your loop continues all by itself, once you allow your loop to loop (currently it goes from 9 to 9 which isn't much of a loop).

Well now I'm completely stumped. Can you please tell me which numbers I switch? I'm really confused.

Originally Posted by CplusplusNewb

Well now I'm completely stumped. Can you please tell me which numbers I switch? I'm really confused.

If you want to change going from 0 to 9 into going from 9 to 0, then perhaps you should switch 0 and 9.