Thread: How to draw shapes with only for loops?

you could use a 2d array for it, you need to be able to store and check whether it is a "#" or a "-", and you can't do that with cout and cin(?). here's some code below, as you can see you have to set the values of the array before you use it otherwise you'd just have a block of 0's (you could also set these by reading values from a file)

Code:

int screen[10][8] = {1, 0, 0, 0, 0, 0, 0, 0,
		     1, 1, 0, 0, 0, 0, 0, 0,
		     1, 1, 1, 0, 0, 0, 0, 0,
		     1, 1, 1, 1, 0, 0, 0, 0,
		     1, 1, 1, 1, 0, 0, 0, 0,
		     1, 1, 1, 1, 1, 0, 0, 0,
		     1, 1, 1, 1, 1, 0, 0, 0,
		     1, 1, 1, 1, 1, 1, 0, 0,
		     1, 1, 1, 1, 1, 1, 1, 0,
		     1, 1, 1, 1, 1, 1, 1, 1}; //[row][column] 10 down eight across

//"draw" your triangle
for (int row = 0; row < 9; row++){
	for (int column = 0; column < 7; column++){
		if (screen[row][column] == 1){
			cout << "#";
		}
		else{
			cout << "-";
		}
	}
	cout << "\n";
}
cout << "\n";
//flip  # into - and vice versa
for (int row = 1; row < 10; row++){ // for some reason 0 and 9 was making this get offset by one line? however this should make it go out of the array... but it doesn't...
	for (int column = 7; column > 0; column--){//draw last column first and first column last, thus flipping the image horizontally
		if (screen[row][column] == 1){
			cout << "#";
			}
		else{
			cout << "-";
		}
	}
	cout << "\n";
}
cout << "\n";