Thread: Storing a number in an array

Is there a fast way to store a number in an array like:

Input: 234586349

becomes

Code:

int array[] = {2,3,4,5,8,6,3,4,9}

Right now my method is very tricky :/

To get the 6, I have to do:

Code:

int a= 234586349 / static_cast<int>(pow(10.0,3));                         // gives 234586
int b = (234586349 / static_cast<int>(pow(10.0,4))) * 10;              // gives 234580

int x = a-b;       // gives 6

Then somehow I have to use a FOR function to get all the digits... is there a better way?
(Preferably one that doesn't involve floating numbers and static_casts I always get into trouble around them >_<)

Thanks!

Code:

#include <iostream>
#include <sstream>
using namespace std;

inline int cToInt(const string& s){
	istringstream i(s);
	int x;
	i >> x
	return x;
}

int main(){
	string  x = "123456789";
	int array[9];
	
	for(int i = 0; i < 9; i++){
		array[i] = cToInt(x.substr(i, 1));
		cout << array[i] << " ";
	}
}

[39] Miscellaneous technical issues, C++ FAQ Lite

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