Thread: Full square

Well... what have you tried?

this is what i have now

Code:

#include <stdio.h>

int main(void)
{
   int row;
   int column;
   int x;



  printf("Enter a number of row to be printed\n" );
   scanf ( "%d", &x );

   row = x;
   
   while ( row > 0 ) 
   {
        printf("*");
        row--;
   }
   printf("\n");

   row = x;
   column = x;

return 0;

}

Filled square or empty square?

If you are using C++ and not just C you should use cout/cin and not printf().

Also this:

Code:

   scanf ( "%d", &x );
   row = x;

can be simply done like this:

Code:

   scanf ( "%d", &row );

Well, you print a line.Read also columns and reapeat "columns times" your program. And you will print eventually a square.

Do some input checking if it is 1-20 if you want. Here is how your program should look (one way to do it)

Code:

while (columns > 0)
{
   while (rows > 0)
   {
       //rest of code
   }
   //rest of code
}

Is there way to just use printf and loop?

Code:

int main(void)
{
   int row;
   int column;
   int x;



  printf("Enter a number of row to be printed\n" );
   scanf ( "%d", &row );

   row = x;
   while (column > 0){
   while ( row > 0 ) {
        printf("*");
        row--;
   }
   printf("\n");

   row = x - 2;
   column = x;
   }
return 0;
}

is this what you told me?

printf pwnz cout every day of the week, especially since cout is (or at least used to be) implemented using printf.

plus its really easy to change a printf statement into a sprintf or fprintf, try doign a fcout or scout

you can implement the whoel thing as a single for loop

Can anyone tell me if its possible to do with printf and while and keep it simple( nothing like cout, cin, sprintf etc.), im just beginner. If it is possible can you tell me how should i modify my code?