vector of function objects

**idleman** · 09-11-2009

Hi all, I want to be able to do this:

Code:

std::vector<???> vec; 
vec.push_back(boost::bind(&testClass::run,t));
vec.push_back(boost::bind(&testfunc));

for(int i = 0; i <vec.size(); ++i) // invoke all function objects in vec...
{
	vec[i](); 
}

How do i accomplish this? All functions objects is invoked in the same way by the operator () but I have no idea how I make a vector of such objects, I tried first with a void (*)() but of course didn't it work, as I thought

I have one ugly solution and it is to make a abstract class and then make a virtual method and use polymorphism.

Thanks in advance.

**Elysia** · 09-11-2009

Use an extra abstraction:

Code:

class CFunctorBase
{
public:
    virtual void operator () = 0;
};

template<typename T> class CFunctor: public CFunctorBase
{
public:
    FunctorBase(T Functor): m_Functor(Functor) { }
    virtual void operator () { m_Functor(); }
private:
    T m_Functor;
};

template<typename T> T* CreateFunctor(T* Functor)
{
    return Functor;
}

std::vector< boost::shared_ptr<FunctorBase> > v;
v.push_back( CreateFunctor(new Functor(boost::bind(...)) );

**Sebastiani** · 09-11-2009

I've never used it myself, but I'm assuming like std::vector< boost::function< void ( * )( ) > > should work.

**Elysia** · 09-11-2009

void (*) () doesn't work for member function pointers!

**Codeplug** · 09-11-2009

boost::function<void ()> seems appropriate.
Tutorial

gg

**Sebastiani** · 09-11-2009

void (*) () doesn't work for member function pointers!

Well I know that. I just assumed boost::function would specialize it appropriately.

I guess not.

Doesn't seem very handy, though, IMO.

**idleman** · 09-11-2009

I fixed it, thanks for your answers

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