Thread: HEX-numbers after incrementation x in for-loop.

SORRY FOR THE DOUBLE POST IN THE FORUM, PLEASE ADMIN REMOVE ONE OF THEM, THANKS

Hello Folks,

I made a little simple program to practice C++, My goals was too see how the two different methods of incrementation (example: x++ and ++x) would be handled in a for-loop.

this is the program:

Code:

#include <iostream>

using namespace std;

void ForIncrementFront()
{
    for(int x = 0; x < 10; ++x)
    {
        cout << x << "\t";
    }
}

void ForIncrementBehind()
{
    for(int x = 0; x < 10; x++)
    {
        cout << x << "\t";
    }
}

int main()
{
    cout << "Function: ForIncrementFront  (++x)\n";
    ForIncrementFront();
    cout << "Function: ForIncrementBehind (x++)\n";
    ForIncrementBehind();

    return 0;
}

this was my output:

Code:

Function: ForIncrementFront (++x):
0 1 2 3 4 5 6 7 8 9 F
Function: ForIncrementBehind (x++):
0 1 2 3 4 5 6 7 8 9

The output of function ForIncrementFont surprised me a little bit because 10 is printed as F and not as 10. what I would like to know is why F instead of 10?, is this a proof of the fact that the PC "speaks" only Hexadecimal and binary? if this is true, why is the output of the code below: 10.

Code:

cout << 9+1;

I hope you understand my question. Sorry if my English grammar is bad, I´am dutch.