Thread: Can a pointer accept user input?

For loops do not have 3 semicolons. Look at the simplest case:

Code:

for(int i = 0; i < something; i++)

Oh, right...duh!
I knew that, but didn't remember to visualize what it would look like if it had all 3 fields.
Forget I even said that...

So I suppose if I removed that last semicolon in the first for loop I wrote, it would have worked?

So I suppose if I removed that last semicolon in the first for loop I wrote, it would have worked?

correct.

Originally Posted by Elysia

This is true, but probably not what the OP wants, since the function returns nothing (invoking undefined behavior, possibly not compiling).
Let's change that to void.

So I suppose every int function is supposed to return an int then?
Just for the record, the code did compile, when I changed it to the following:

Code:

#include <iostream> 
using namespace std; 

void f(int* p) { 
  if (*p == 1) 
    cout << "You entered 1. Good guess." <<endl; 
  else { 
    cout << "Wrong guess, please try again." <<endl; 
    cin >> *p; 
  } 

} 

int main() { 

  int x; 
  cout << "Please input a number:"<< endl; 
  cin >> x; 
  f(&x); 
  for ( int i; x != 1; ) { 
    cout << "You entered " <<x<< ", wrong guess. Please try again"<<endl; 
    cin >> x; 
  } 
  return 0; 
}

Of course it doesn't handle the cases if a user entered a char, or float. But it was only supposed to be an example anyway for my question, which was whether or not a pointer could accept user input (I assumed it could, but just wanted to make sure).

Thanks for the replies.

Originally Posted by Elysia

No, it returns whatever you want it to return.

Just to be crystal clear, this is all kinds of wrong.

OP, if we consider the parts of a function prototype such as int f (int *p); then, the return value type is int, and you need to return an integer. You are only supposed to omit a return statement if the return type is void.

Originally Posted by iMalc

Always use a reference rather than a pointer if it is not valid for the parameter to be NULL. (except in cases where the function is exported)

His comment was not in regards to reference vs pointer. It was if the function should return the integer from f() instead of passing it back through a reference.

yes of course