Thread: if argv

I'm trying to use an if statement that runs if you have an argv called help, but it doesn't work.

Code:

#include <iostream>

using namespace std ;

int main(int argc, char* argv[])
{

  if ( argc ) {
    if ( argc == "help" ) {
    cout << "You said " << argv[1] << " just then.\n" ;
    }
    else {
    cout << "What?\n" ;
    }
  }

}

This is, as far as I could tell, right, but it outputs 'What?' every time, regardless.

argc (argument count) is an integer representing the total number of arguments, including the name of the application

argv is an cstring array with the arguments, argv[0] is the first argument (which will always be the name of your application)

Code:

// Check all arguments (skip the first) to see if any are "help"
for (int i = 1; i < argc; ++i) {
	if (string (argv[i] ) == "help")
		cout << "Argument " << i + 1 << ": help\n";
	else
		cout << "Argument " << i + 1 << ": unknown\n";
}