Thread: Error declaring default argument to friend function

I'm stumped. This only gives me an error if the class is a template and the functions are declared within the class. Here's a stripped-down example:

Code:

template < typename T >
struct foo
{
    friend void bar( foo< T > const& data, bool condition = false )
    {    }
    
    friend void qux( foo< T > const& data )
    {        
        bar( data );
    }
};

int main( void )
{
    qux( foo< int >( ) );
    return 0;
}

The error doesn't make much sense either:

"default argument given for parameter 2 of `void bar(const foo<int>&, bool)' after previous specification in `void bar(const foo<int>&, bool)'.

Any ideas?

OK, well, I think I've got it now. Seems as though friend functions (of templates) are supposed to be declared as templates themselves (even if within the class). I didn't think it was necessary since it usually compiles without complaint; I just figured that the compiler was deducing the parameter (given that it's declared within the class, after all). That would be the most logical thing to do, anyway. Go figure.