Write a program that uses a loop to display the characters for each ASCII code 32 through 127. Display 16 characters on each line with one space between characters.
We are using the Starting out with C++ Early Objects 6th edition. I really don't know how to start this program, I'm not sure if it wants me to display ever character, or if I have to do get the user to input numbers and give me the characters that it should be or the other way around. If you can please help me that would be great.
Sounds very self-explanatory to me. Use a loop from 32 to 127 to display the characters with those values, no user input needed.
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You can display your output with the printf function. Use the "%c" formatting string to display your loop counter as a character. #include <stdio.h> to be able to use printf.
Although you could do as Zlatko suggests, I suggest that you practice with more C++ specific I/O instead. You could choose to use a loop counter variable of type char, or of say, type int but cast to char for printing.Originally Posted by Zlatko
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Oh, sorry, I thought I was in the other forum.Although you could do as Zlatko suggests, I suggest that you practice with more C++ specific I/O instead.
Yeah, what Zlatko lost me, I haven't seen that before...
Anyways this is what I have right now, but it is annoying because it wants 16 chars on each line, and it displays the first number twice...
So I guess I might have to do a few loops, maybe one loop per line...
Source code
This is what it looks likeCode:#include<iostream> using namespace std; int main() { //declaration of variables int dec = 32; //loop while(dec <= 127) { cout<< dec << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << endl; } system("pause"); return 0; }
47 46 45 44 43 42 41 40 39 38 37 36 35 34 33 32
62 61 60 59 58 57 56 55 54 53 52 51 50 49 48 47
77 76 75 74 73 72 71 70 69 68 67 66 65 64 63 62
92 91 90 89 88 87 86 85 84 83 82 81 80 79 78 77
107 106 105 104 103 102 101 100 99 98 97 96 95 94 93 92
122 121 120 119 118 117 116 115 114 113 112 111 110 109 108 107
137 136 135 134 133 132 131 130 129 128 127 126 125 124 123 122
Press any key to continue . . .
Look up the difference between postfix and prefix increment on the forum.
If you search the forum, you'll find plenty of posts about it, and can fix your code.
edit: Oh wait, try printing char(dec++).
Last edited by whiteflags; 06-29-2009 at 02:41 PM.
Hint:
Loops can be nested within each other.
Woop?
That's just printing the numbers 32 to 127.
You need to print the ASCII chars for those numbers (i.e. use a char instead of an int).
To split lines every 16 chars you can either have 2 loops, or if you've learned about the % operator you can use that instead.
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I still don't get the postfix and the prefix, if someone could give me a hand that would be great. So help with the chars displaying twice, I don't know how to fix that.
My teacher didn't really explain them...
anyways this is the code
This is the Screen OutputCode:#include<iostream> using namespace std; int main() { //declaration of variables char dec = 32; //loop while(dec <= 110) { cout<< dec << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << endl; while ( dec == 122 || dec > 127) { cout<< dec << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++ << " " << dec++<<endl; } } system("pause"); return 0; }
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So here's the thing. Prefix or postfix, you're not allowed(*) to do ++ more than once in a statement. So you need to split this up into code that is much easier, by only having one printed char per "cout" statement.
(*)Well, you're allowed, but the compiler is also allowed to do anything it wants -- there's no way to guarantee you'll get the order you desire.
