Thread: conversion error?

Megatron says..........hoping not to bother anyone too much with his dumb questions...........

why do i get a possible loss of data warning on this

float overtime1 = base * 1.5;
float overtime2 = base * 2.0;

at this point in the program there are already values entered for base
the warning also says "convrting double into float"
but ive never ever even declared a double in my program

these arent actually errors but the compiler issues a warning
but ive been told never to ignore a warning any ways thanks for any help i recieve

A constant literal such as 1.4 or 2.5 are considered double by the compiler, you can either declare your overtime variables as double or cast the literals.
float overtime1 = base * (float)1.5;
or
float overtime1 = base * 1.5f;

-Prelude

thanks alot you dont even know how much i get that
not no more though