# Off by a penny problem

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• 05-18-2009
ninety3gd
Off by a penny problem
Getting the off by a penny problem...

Enter an amount in double, for example 11.56: 12.35
Your amount 12.35 consists of
12 dollars
1 quarters
0 dimes
1 nickels
4 pennies

Press ENTER to continue...

Where do I properly add my + .00001

I tried a few places but it did not work...any insight...

Code:

```#include <iostream> using namespace std; int main() {   // Receive the amount   cout << "Enter an amount in double, for example 11.56: ";   double amount;   cin >> amount;   int remainingAmount = static_cast<int>(amount * 100);   // Find the number of one dollars   int numberOfOneDollars = remainingAmount / 100;   remainingAmount = remainingAmount % 100;   // Find the number of quarters in the remaining amount   int numberOfQuarters = remainingAmount / 25;   remainingAmount = remainingAmount % 25;   // Find the number of dimes in the remaining amount   int numberOfDimes = remainingAmount / 10;   remainingAmount = remainingAmount % 10;   // Find the number of nickels in the remaining amount   int numberOfNickels = remainingAmount / 5;   remainingAmount = remainingAmount % 5;   // Find the number of pennies in the remaining amount   int numberOfPennies = remainingAmount;   // Display results   cout << "Your amount " << amount << " consists of \n" <<     "\t" << numberOfOneDollars << " dollars\n" <<     "\t" << numberOfQuarters << " quarters\n" <<     "\t" << numberOfDimes << " dimes\n" <<     "\t" << numberOfNickels << " nickels\n" <<     "\t" << numberOfPennies << " pennies";     /* Scaffolding code for testing purposes */ cin.ignore(256, '\n'); cout << "Press ENTER to continue..." << endl; cin.get(); /* End Scaffolding */   return 0; }```
• 05-18-2009
rossipoo
Before division I think. But the real solution is to keep track of money using an integer to represent pennies or whatever the smallest unit is.
• 05-18-2009
ಠ_ಠ
hmm... it works for me