Thread: Returning 2D Array

Was having trouble finding out how to properly return a 2D array in a function. I have seen 1D array, but no more as of yet. If somebody has an example I could use one along with how the call would look for it. If pointer is involved too thats okay.

well I had this and I was trying to break it down into a:

Code:

void getData(){}
int findLow(){}
double calcAvg(){}
void Display(){}

int main()
{Vars

getData();
low=findLow();
avg=calcAvg;
Display();
}

in order to put the Averages & Lowests into an array rather than calculate, displaying & then losing them after & the issue is returning an array to the function & also not sure yet how to call them back into main.

Code:

#include<iostream>
#include<iomanip>
using namespace std;

void getData(int score[][4], int rows, int &low, double &avg)
{
	for(int R=0; R < rows; R++)
	{
		int TOT=0;
		low = 100;

		for(int C=0; C < 4; C++)
		{
			do
			{
				cout << "Enter test score " << (C+1) << " for student " << (R+1) << ": ";
				cin >> score[R][C];
			}while(score[R][C] < 0 || score[R][C] > 100);

			TOT += score[R][C];

			if (score[R][C] < low)
				low = score[R][C];
		}

		avg = (TOT - low) / 3.0;

		cout << fixed << setprecision(2);
		cout << endl;
		cout << "Dropped Grade: " << low << endl;
		cout << "Average: " << avg << endl;
	}
}

int main()
{
	int sc[3][4], low;
	double avg;

	getData(sc, 3, low, avg);
	return 0;
}

I also realize you can not return an array but return the pointer just not sure how to go about it here.