Code://Here is what I got so far #include <iostream> using namespace std; int main () { int n, median; double standarddeviation; int num [31]={12, 13, 15, 16, 18, 19, 21, 34, 57, 32, 38, 213, 10, 14, 156, 172, 134, 143, 132, 139, 751, 30, 31, 81, 23, 41, 24, 51, 75, 91, 1234}; int sum= 0; for (n=0; n<31; n++) sum = sum+num [n]; double average=sum/31.0; standarddeviation=(num[n]-average)*(num[n]-average);//I want to multiply every number by itself, subtract from the mean and son on but I can't seem to get it cout<< sum<<endl; cout<<average<<endl; cout<<standarddeviation; return 0; }
Originally Posted by iMalc
