Thread: C++ functions vs. C functions

Is there an equivalent C++ function for every C function?

Or sometimes we should use C function in C++ code?

For example memset() is a C function but it seems that it much simple to set charset[]
to '0' with it.

Code:

char charset[256];
memset(charset,0,sizeof(charset));

Or it seems entirely possible that that char array was never intended to hold a nul-terminated string. In that case, std::fill is the C++ equivalent.

An even simpler way to initialize the array with zero's is this:

Code:

char charset[256] = {0};

As others have said, there's no 1 to 1 mapping of C to C++ functions. I think most C functions should have some type of C++ equivalent, although depending on what you are doing, it might be faster to write using C functions in some places...

Well, for char arrays GCC has this:

Code:

  // Specialization: for one-byte types we can use memset.
  inline void
  fill(unsigned char* __first, unsigned char* __last, const unsigned char& __c)
  {
    __glibcxx_requires_valid_range(__first, __last);
    const unsigned char __tmp = __c;
    std::memset(__first, __tmp, __last - __first);
  }

  inline void
  fill(signed char* __first, signed char* __last, const signed char& __c)
  {
    __glibcxx_requires_valid_range(__first, __last);
    const signed char __tmp = __c;
    std::memset(__first, static_cast<unsigned char>(__tmp), __last - __first);
  }

  inline void
  fill(char* __first, char* __last, const char& __c)
  {
    __glibcxx_requires_valid_range(__first, __last);
    const char __tmp = __c;
    std::memset(__first, static_cast<unsigned char>(__tmp), __last - __first);
  }

But indeed = {0} is the way to fill an array with all zero values.

Code:

char charset[256] = {0};

Well that just cant be simpler. Great!

I thought it would only have assigned to the first element.

Thanks everybody!

Note that this only works if you want to fill an array or struct with zeros. Recently...