Thread: string manipulation

i have a problem:

i need to take the first character from a string and place it at the end of the string...how can i do this?

example:
input "hello"
output "elloh"

i've tried setting a char variable equal to the first character in the string, but then how do i put it at the end? strcat() gives an illegal operation on the second parameter, saying i need a (const char *), instead of a (char).

can someone help?

#include "stdio.h"
#include "conio.h" // getch ()
#include "windows.h" // strlen()

int get_strlen(char * string);

Code:

int main()
{
	char input[80] = { NULL }, // { NULL } sets all the subscript to NULL
	     ch;
	int     idx = 0;

	printf("\n Input : ");
	gets(input);

	printf("\n input = [ %s ] ",input);
	
	// strlen() returns the number of chars in input
	idx = strlen(input);
	// idx = get_strlen(input);

	// right here is where it's done - swap first and last char
	ch = input[--idx];
	input[idx] = input[0];
	input[0] = ch;

	printf("\n input = [ %s ] ",input);
	printf("\n ------\n\n");

	getch(); // press any key to continue

	return 0;
}

// Use this is you don't have strlen() or windows.h
int get_strlen(char * str)
{
	int nbr = 0;

	// \0 = NULL
	while(str[nbr] != '\0')
		nbr++;

	return nbr;
}

I posted another thing similiar to this one on the board.
* Note : written in C - i hope you can get ideas from it.

oh... ok. sorry

thanks to everyone who has helped...now i have this function:

char *convert(char *theString)
{
int index = strlen(theString);
char first = theString[0];
for(int i = 1; i < index; i++)
{
theString[i - 1] = theString[i];
}

theString[index - 1] = first;

return theString;
}

this gives me no compile errors, but my program crashes with an illegal operation. any ideas?

since theString is passed to the function as a parameter it doesn't need to be returned in the fomral sense.

be sure you have the header file for strlen() included in your project.

thanks again for the reply...i included the header for strlen(), and changed the function so it doesn't return the string, but i still get the illegal operation...

here is the entire program:

#include <iostream>
using std::endl;
using std::cout;
using std::cin;

#include "string.h"

void convert(char *theString);

int main()
{
convert("string");
return 0;
}

void convert(char *theString)
{
int index = strlen(theString);
char first = theString[0];
for(int i = 1; i < index; i++)
{
theString[i - 1] = theString[i];
}

theString[index - 1] = first;
}

Prelude,

Yeah, I think am getting to used to my compiler ... I should have known that strlen() was defined in string.h, heh.
And yes I know "input[80] = { 0 };" is not a good idea. (But it works for me)

I didn't know that about gets() (why?) , but I hate useing scanf(), it doesn't look that great.

unfortunately "string" is not a char * so you can't pass it to convert.

Try doing this:
#include <cstring> //the header file in your compiler likely to have strlen() in it

instead of this:

#include "string.h" // the "" syntax is for header files in the same directory as the .exe file of your program, and I doubt that's where you would find string.h, even if your compiler had it, which it probably doesn't if you don't need to use the .h syntax for precompiled headers included in your programs.

then in main() do this:

char dummy[10] = "string";
convert(dummy);

and recompile.

Good luck.