How do you do it? Like for example, you have 1234 and you want one-two-three-four to printed out. I was trying to use cases but I couldn't do much since am very new to the whole thing. Any suggestions are welcome. Yes I searched the forum but couldn't find a very good answer to my question. Thanks
Funny, because I'm sure this has been discussed at least a dozen times since I became a member less than two years ago.
What part are you struggling with? Splitting a number into digits, or making words from digits?
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Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
First of all, to be more specific, I have to change four digit numbers into words. The part I am struggling is making words out of the digits.
(1) Convert number to string
(2) For each digit in string, print corresponding word
You could use if/else statements here, or simply store the words in an array where digit - '0' yields the appropriate index.
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
If it's an integer, why not simply use the integer divide/modulo method - then use index into an array? There's no benefit in making it a string first, as I can see.
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Mats
Compilers can produce warnings - make the compiler programmers happy: Use them!
Please don't PM me for help - and no, I don't do help over instant messengers.
That works, but then the output would have to be reversed.
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
Here is what I got so far. Please note that I can't use arrays because I don't know them. I am a complete beginner. So I just want use to loops and I thought if is the more appropriate one. My problem is in getting to print out the words of more than one digit. So if I have 4327, I want four-three-two-seven to be printed out. That is where I am stuck and I don't know arrays or pointers, just a bit of loops.
Code:#include <iostream> using namespace std; int main (){ int num,digit1,digit2,digit3,digit4; cout<<"Please enter a four digit number"; cin>>num; digit1=(num/1000); digit2=(num/100)%10; digit3=(num/10)%10; digit4=num%10; if (digit1,digit2,digit3,digit4==0) cout<<"zero"; else if (digit1,digit2,digit3,digit4==1) cout<<"one"; else if (digit1,digit2,digit3,digit4==2) cout<<"two"; else if (digit1,digit2,digit3,digit4==3) cout<<"three"; else if (digit1,digit2,digit3,digit4==4) cout<<"four"; else if (digit1,digit2,digit3,digit4==5) cout<<"five"; else if (digit1,digit2,digit3,digit4==6) cout<<"six"; else if (digit1,digit2,digit3,digit4==7) cout<<"seven"; else if (digit1,digit2,digit3,digit4==8) cout<<"eight"; else if (digit1,digit2,digit3,digit4==9) cout<<"nine"; return 0; }
Last edited by Dontgiveup; 03-28-2009 at 03:58 PM.
I just get last digit printed out. If I put in 4357 for example, I will only get seven. How can I make it to get me four-three-five-seven?
I suppose the question that must be asked is why do you think "digit1,digit2,digit3,digit4" is going to do what you want?
I think it is because I have to print the word for each digit? I mean if someone inputs 1963, then I want one-nine-six-three printed out. That is just what I thought and I can be wrong.Originally Posted by tabstop
Then you would need to do them in order, no? First digit first, then second digit second, etc.
that's equivalent to if (digit4 == 0) cout << "zero";
the proper statement would be
I don't think you want to use that method of reasoning though, because you program will only be able to handle 0000, 1111, 2222, etc...Code:if (digit1 == 0 && digit2 == 0 && digit3 == 0 && digit4 == 0) cout << "zero"
HOW TO MAKE AN ARRAY:
what you really want your program to do is this:Code:int digit[4]; // this will make an array with 4 cells, cell 0, 1, 2, & 3 digit[0] = 1; // this will store 1 inside the first cell in digit digit[1] = 2; // this will store 2 inside the 2nd cell in digit digit[4] = 5; // BE CAREFUL this cell doesn't exist! make sure that your program doesn't try to access cells outside the bounds of the array
Code:int main() { int num, digit[4], i; cout<<"Please enter a four digit number"; cin>>num; digit[0]=(num/1000); digit[1]=(num/100)%10; digit[2]=(num/10)%10; digit[3]=num%10; for (i = 0; i < 4; i++) { if (digit[i] == 9) cout << "nine"; else if(digit[i] == 8) cout << "eight"; else if(digit[i] == 7) cout << "seven"; // etc if (i) cout << "-"; // prints - as long as i != 0 } }
Last edited by ಠ_ಠ; 03-28-2009 at 05:57 PM.
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Thank you, you really helped me understand it at last. Here is my full code and it works. I guess it is going through a very long way but I guess it is what a beginner deserves? Is there any shorter way using loops? I haven't s till learn pointers and arrays though I heard they can be used as short-cuts. But thank you so much.
Code:#include <iostream> using namespace std; int main (){ int num,digit1,digit2,digit3,digit4;// cout<<"Please enter a four digit number"; cin>>num; digit1=(num/1000); digit2=(num/100)%10; digit3=(num/10)%10; digit4=num%10; if (digit1==0) cout<<"zero"; else if (digit1==1) cout<<"one"; else if (digit1==2) cout<<"two"; else if (digit1==3) cout<<"three"; else if (digit1==4) cout<<"four"; else if (digit1==5) cout<<"five"; else if (digit1==6) cout<<"six"; else if (digit1==7) cout<<"seven"; else if (digit1==8) cout<<"eight"; else if (digit1==9) cout<<"nine"; if (digit2 ==0) cout<<"zero"; else if (digit2==1) cout<<"one"; else if (digit2==2) cout<<"two"; else if (digit2==3) cout<<"three"; else if (digit2==4) cout<<"four"; else if (digit2==5) cout<<"five"; else if (digit2==6) cout<<"six"; else if (digit2==7) cout<<"seven"; else if (digit2==8) cout<<"eight"; else if (digit2==9) cout<<"nine"; if (digit3==0) cout<<"zero"; else if (digit3==1) cout<<"one"; else if (digit3==2) cout<<"two"; else if (digit3==3) cout<<"three"; else if (digit3==4) cout<<"four"; else if (digit4==5) cout<<"five"; else if (digit3==6) cout<<"six"; else if (digit3==7) cout<<"seven"; else if (digit3==8) cout<<"eight"; else if (digit3==9) cout<<"nine"; if (digit4==0) cout<<"four"; else if (digit4==1) cout<<"one"; else if (digit4==2) cout<<"two"; else if (digit4==3) cout<<"three"; else if (digit4==4) cout<<"four"; else if (digit4==5) cout<<"five"; else if (digit4==6) cout<<"six"; else if (digit4==7) cout<<"seven"; else if (digit4==8) cout<<"eight"; else if (digit4==9) cout<<"nine"; cin>>num; return 0; }
Not really a solution to your problem directly as I am also a newbie to c++ programming, but a good resource that I'm currently using is "C++ Primer Plus" by Stephen Prata. Unlike many of the other C++ books out there it introduces arrays and pointers quite early on (not that they made much sense at first).
