Thread: Strange behaviour of Ternary

It puts me out '0's before every line. There is nothing in the code to write zeros.
If i take out this line everything goes well. No zeros.

Now i think it could be due to the fact that if the first value is true =0
second value is true =1.

But why would it put it out? If i use the same statement in another program it wont put out zeros. I dont understand.

Code:

#include <cstdio>
#include <windows.h>
#include <iostream>
using namespace std;

HANDLE h = GetStdHandle ( STD_OUTPUT_HANDLE );
WORD wOldColorAttrs;
CONSOLE_SCREEN_BUFFER_INFO csbiInfo;
COORD NewSBSize = GetLargestConsoleWindowSize(h);
SMALL_RECT DisplayArea = {0, 0, 0, 0};
int x=0;
int main()
{
    SetConsoleScreenBufferSize(h, NewSBSize);  // FULLSCREEN
    DisplayArea.Right = NewSBSize.X - 1;
    DisplayArea.Bottom = NewSBSize.Y - 1;
    GetConsoleScreenBufferInfo(h, &csbiInfo);
    wOldColorAttrs = csbiInfo.wAttributes;
    SetConsoleTextAttribute ( h, 8 );
    
    cout<<endl<<endl;
    cout<< "        A         B        C        D        E        F        G       H "<<endl;
    for(int y=0; y<42; y++)
        for(int x=0; x<42; x++)
           
           if(y==1)                          // FIRST LINE OF CHECKERBOARD
                if(x==0)   cout<< "    " ;
                else if(x==1)   putchar(218);
                else if(x==41)  cout<<(char)191 << "\n" <<"    " ;
                else if(x%5==1) putchar(194);
                else            cout<<(char)196<<(char)196;
        
           else if(y%5==1 && 37>y)          // HORIZONTAL  LINES
                if(x==0)        cout<< "";
                else if(x==1)   putchar(195);
                else if(x==41)  cout<<(char)180<< "\n" <<"    " ;
                else if(x%5==1) putchar(197);
                else            cout<<(char)196<<(char)196;    //horizontal lines
                                                                             
           else if(y==41)                  // LAST LINE OF CHECKERBOARD
                if(x==0)        cout<< "";
                else if(x==1)   putchar(192); 
                else if(x==41)  cout<<(char)217<< "\n" << "   " ;
                else if(x%5==1) putchar(193);
                else            cout<<(char)196<<(char)196;
         
           else if(y!=0)                  // VERTICAL LINES
                if(x==41)       cout<<(char)179 << "\n"<< (y%5==1) ? cout<<"  2" : cout<<"  3";  //  <-- THIS LINE!!!
                else if(x%5==1) cout<<(char)179 <<"        ";
         
    cout<< endl;
    system("pause");
    return 0;
}

Well . . .

Code:

cout<<(char)179 << "\n"<< (y%5==1) ? cout<<"  2" : cout<<"  3";

Examine it.
This does not do what you think:

Code:

 ? cout<<"  2" : cout<<"  3";

It's printing the return value of

Code:

cout::operator<<()

, I believe.

Correct me if I'm wrong . . . simply remove the "cout<<" and all should be fine.

Fix + tidyup suggestion:

Code:

cout << static_cast<char>(179)
     << ((y%5==1) ? "\n  2" : "\n  3");

Brilliant! Thank you Nightowl and iMalc!