hi,
when casting a float to an int you lose the fractional part of the number . So does the code below round the float up to the next int in the most effective manner. If not could you please show how you would do it?
#include <iostream>
using namespace std;
int main ()
{
double num1 = 0;
int newnum = 0;
cout << endl << "Please Enter a float number and i Will round it up to the next whole number!"
<< endl;
cin >> num1;
newnum = num1 +1;
cout << newnum
<< endl;
return 0;
}
Why not just use the function that the language provides for this.... ciel() . You will find it in math.h or cmath(where its in namespace std)
Free the weed!! Class B to class C is not good enough!!
And the FAQ is here :- http://faq.cprogramming.com/cgi-bin/smartfaq.cgi
This comes from VB, but ought to work in c++:
enter a float, add 0.5, then use floor() to round it out. If the float entered was x.5 or above, you'll round up. Below x.5, you'll round down.
Telling a user to enter a float, but secretly treating it as an int, will only round down. 5.999 will come out as 5, not 6.
Code:inline int Round(const double var) { return var > 0 ? (int)(var + 0.5) : (int)(var - 0.5); }
Making error is human, but for messing things thoroughly it takes a computer
