Thread: Parsing input...

I want to make my prompt somewhat nicer in that a user can enter their input for a fraction in the normal fashion:

i.e. 4/5 6/7

and be able to store the numerators and denominators on the programming side.

i.e.

a = 4
b = 5
c = 6
d = 7

How would I go about doing this?

Originally Posted by Elysia

For this one... I think this should do:

Code:

int num[4];
char op[2];
char temp;
cin >> num[0] >> op[0] >> num[1] >> temp >> num[2] >> op[1] >> num[3];

Obviously, if you want longer inputs or more complex ones, you will have to read it all in one go and parse it from there.

Thought so, was just wondering if there was a very simple way to do it depending on the length/complexity of the input. Got it, thanks.